Statement-I: In aniline, –NH₂ group is strong deactivating group for all ESR.

Statement-II: Aniline does not show Friedel-Craft alkylation reaction.

(1) Both statement-l and statement-II are correct

(2) Both statement-l and statement-II are incorrect

(3) Statement-l is correct and statement-II is incorrect

(4) Statement-l is incorrect and statement-Il is correct

Correct Option - 4


Detailed Solution:

In aniline –NH₂ is strong activating group due to presence of lone pair in nitrogen.

Aniline does not show Friedel-Craft alkylation reaction, because anhydrous AlCl₃ and aniline form salt together

 

<p><span lang="EN-IN">In aniline –NH₂ is strong activating group due to presence of lone pair in nitrogen.</span></p><p><span lang="EN-IN">Aniline does not show Friedel-Craft alkylation reaction, because anhydrous AlCl₃ and aniline form salt together</span></p><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1758794004phpsHULQZ.jpeg" alt="" width="223" height="89" loading="lazy"></picture></div></div><p>&nbsp;</p>

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