The ammonia released on quantitative reaction of urea with sodium hydroxide can be neutralized by
The ammonia released on quantitative reaction of urea with sodium hydroxide can be neutralized by
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>100</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">L</mi> </math> </span> of <span class="mathml" contenteditable="false"> <math> <mn>0.1</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">H</mi> <mi mathvariant="normal">C</mi> <mi mathvariant="normal">l</mi> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>100</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">L</mi> </math> </span>of <span class="mathml" contenteditable="false"> <math> <mn>0.2</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">H</mi> <mi mathvariant="normal">C</mi> <mi mathvariant="normal">l</mi> </math> </span></p>
Option 3 - <p> <span class="mathml" contenteditable="false"> <math> <mn>200</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">L</mi> </math> </span>of <span class="mathml" contenteditable="false"> <math> <mn>0.2</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">H</mi> <mi mathvariant="normal">C</mi> <mi mathvariant="normal">l</mi> </math> </span></p>
Option 4 - <p> <span class="mathml" contenteditable="false"> <math> <mn>200</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">L</mi> </math> </span>of <span class="mathml" contenteditable="false"> <math> <mn>0.4</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">H</mi> <mi mathvariant="normal">C</mi> <mi mathvariant="normal">l</mi> </math> </span></p>
2 Views|Posted 5 months ago
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5 months ago
Correct Option - 2
Detailed Solution:
Moles of moles of
moles of urea
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Ten 2025
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