The CFSE for octahedral [CoCl6]4- is 18,000 cm−1. The CFSE for tetrahedral [CoCl4]2- will be
A: 18,000 cm−1
B: 16,000 cm−1
C: 8,000 cm−1
D: 20,000 cm−1
The CFSE for octahedral [CoCl6]4- is 18,000 cm−1. The CFSE for tetrahedral [CoCl4]2- will be
A: 18,000 cm−1
B: 16,000 cm−1
C: 8,000 cm−1
D: 20,000 cm−1
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Correct option: A
CFSE for octahedral and tetrahedral complex is related as
Δt = Δ0
Where Δ0= CFSE for octahedral complex
Δ0= CFSE for tetrahedral complex
Δ0=1800 cm−1
Δt =49*18000=8000 cm−1
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine 2025
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