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The cis-alkenes are formed by the reduction of alkynes with

Option 1 -

NaBH4

Option 2 -

Na/liq. NH3        

Option 3 -

H2 – Pd/C, BaSO4            

Option 4 -

Fe + HCl

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago
    Correct Option - 3


    Detailed Solution:

    R C = C R ' + H 2 ? B a S O 4 P d / C

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