The concentration-time dependence for a 1st order reaction is as shown in the graph: At which point on the curve, the rate of reaction is fastest?
The concentration-time dependence for a 1st order reaction is as shown in the graph: At which point on the curve, the rate of reaction is fastest?
Option 1 - <p>B</p>
Option 2 - <p>A</p>
Option 3 - <p>C</p>
Option 4 - <p><span lang="EN-IN">All point have same rate</span></p>
2 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
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Answered by
4 months ago
Correct Option - 2
Detailed Solution:
1st order reaction is the fastest at the starting of the reaction then it decrease also you can see the slope which is equal to rate.
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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