The correct order of the ionic radii of O²⁻, N³⁻, F⁻, Mg²⁺, Na⁺ and Al³⁺ is:


Option 1 - <p>N³⁻ &lt; O²⁻ &lt; F⁻ &lt; Na⁺ &lt; Mg²⁺ &lt; Al³⁺<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>Al³⁺ &lt; Mg²⁺ &lt; Na⁺ &lt; F⁻ &lt; O²⁻ &lt; N³⁻<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>Al³⁺ &lt; Na⁺ &lt; Mg²⁺ &lt; O²⁻ &lt; F⁻ &lt; N³⁻</p>
Option 4 - <p>Al³⁺ &lt; Na⁺ &lt; Mg²⁺ &lt; O²⁻ &lt; F⁻ &lt; N³⁻</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 2
Detailed Solution:

In isoelectronic species nuclear charge can be approximated as
Nuclear charge ≈ z / no. of electrons
Al³? Mg²? Na? F? O²? N³?
Nuclear Charge: 13/10 12/10 11/10 9/10 8/10 7/10
Minimum nuclear charge is in N³? and maximum is in Al³?
So order should be
Al³? < Mg²? < Na? < F? < O²? < N³?

...Read more

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

Among isoelectronic monoatomic species, size is inversely proportional to atomic number. Hence among isoelectronic species Na? , O²? , N³? , F? (having the nearest noble gas configuration);
Order of size is Na? < F? < O²? < N³?
N³? has least atomic number hence the largest size

...Read more

Electron gain enthalpy increases with electro negativity chlorine has higher electron gain enthalpy than fluorine (exception)

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Classification of Elements and Periodicity in Properties 2025

Chemistry Classification of Elements and Periodicity in Properties 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering