The energies E1 and E2 of two radiations are 100 kJ and 200 kJ respectively. The relation between their frequencies i.e. v1 and v2 will be
The energies E1 and E2 of two radiations are 100 kJ and 200 kJ respectively. The relation between their frequencies i.e. v1 and v2 will be
Option 1 - <p><span lang="EN-IN">v</span><span lang="EN-IN">1 </span><span lang="EN-IN">= 2v</span><span lang="EN-IN">2 </span></p>
Option 2 - <p><span lang="EN-IN">2v</span><span lang="EN-IN">1 </span><span lang="EN-IN">= v</span><span lang="EN-IN">2 </span></p>
Option 3 - <p><span lang="EN-IN">v</span><span lang="EN-IN">1 </span><span lang="EN-IN">= v<sub>2</sub>/</span><span lang="EN-IN">4 </span></p>
Option 4 - <p><span lang="EN-IN">v</span><span lang="EN-IN">1 </span><span lang="EN-IN">= 4v</span><span lang="EN-IN">2 </span></p>
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a year ago
Correct Option - 2
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Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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