The energies E1 and E2 of two radiations are 100 kJ and 200 kJ respectively. The relation between their frequencies i.e. n1 and n2 will be
The energies E1 and E2 of two radiations are 100 kJ and 200 kJ respectively. The relation between their frequencies i.e. n1 and n2 will be
Option 1 - <p>V<sub>1 </sub>= 2V<sub>2</sub></p>
Option 2 - <p>2V<sub>1 </sub>= V<sub>2</sub></p>
Option 3 - <p>V<sub>1 </sub>= V<sub>2</sub>/4</p>
Option 4 - <p>V<sub>1 </sub>= 4V<sub>2</sub></p>
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4 months ago
Correct Option - 2
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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