The energy of an electron in the ground state for ion is , then that for an electron in state for ion in J is
The energy of an electron in the ground state for ion is , then that for an electron in state for ion in J is
Option 1 - <p>-x</p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mo>−</mo> <mfrac> <mrow> <mi>x</mi> </mrow> <mrow> <mn>9</mn> </mrow> </mfrac> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mo>−</mo> <mn>4</mn> <mi>x</mi> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mo>−</mo> <mfrac> <mrow> <mn>4</mn> </mrow> <mrow> <mn>9</mn> </mrow> </mfrac> <mi>x</mi> </mrow> </math> </span></p>
4 Views|Posted 7 months ago
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7 months ago
Correct Option - 1
Detailed Solution:
For ,
For ,
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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