The enthalpy of atomisation for the reaction CH4(g)→ C(g) + 4H(g) is 1665 kJ/ mol. What is the bond energy of C–H bond?
The enthalpy of atomisation for the reaction CH4(g)→ C(g) + 4H(g) is 1665 kJ/ mol. What is the bond energy of C–H bond?
-
1 Answer
-
This is a Short Answer Type Questions as classified in NCERT Exemplar
The reaction presented in the question is
CH4 (g)→C (g) + 4H (g)
Now, ΔaH = 1665 kJ/mol
The mean bond enthalpy of the C-H bond should be used here. For the atomisation of 4 moles of C-H bonds, the value is 1665 kJ/mol. So, per mole energy = 1665/4 = 416.2 kJ / mol
Similar Questions for you
Kindly go through the solution
(1) [Ni (NH3)6]+2 → Ni+2 → d8, C. No. = 6,
SP3d2, Para
(2) [Co (H2O)6]+2 → Co+2 → d6, C. No. = 6
d2sp3, Dia
(3) [Ti (H2O)6]+3 → Ti+3 → d1, C. No. = 6
d2SP3, Para
(4) [Co (NH3)6]+3 → Co+3 → d5, C. No. = 6
d2sp3, Para
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers