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The equilibrium constant for the reaction Zn(s) + Cu2+ (aq.) ->Cu(s) + Zn2+ (aq.), E° = 1.10 V at 298 K is

Option 1 -

1042.38

Option 2 -

1028.56

Option 3 -

1050.73

Option 4 -

1037.22

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:
    Kindly go through the solution

     

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