The five successive ionization enthalpies of an element are 710, 1414, 2550, 28124 and 33845 kJ mol?¹. How many moles of H?SO? will be needed to react completely with 4 moles of the metal hydroxide?

Option 1 -

Option 2 -

Option 3 -

Option 4 -

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Answered by

Raj Pandey | Contributor-Level 9

3 weeks ago

Correct Option - 2

Detailed Solution:

As the difference in $3^{rd}$ $^{}$ and $4^{th}$ $^{}$ ionisation energy is high so atom contains 3 valence electrons. Hence, valency of the atom is 3 and the metal is trivalent. 4 mole of trivalent metal hydroxide will react with 6 mole of $H_{2} {S O}_{4}$ $_{}_{}$ , $(2 M (O H)_{3} + 3 H_{2} {S O}_{4} ? M_{2} {({S O}_{4})}_{3} + 6 H_{2} O)$

As the difference in <math> <msup> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow> <mrow> <mtext>rd</mtext> <mtext> </mtext> </mrow> </mrow> </msup> </math> <math><msup><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msup></math> and <math> <msup> <mrow> <mrow> <mn>4</mn> </mrow> </mrow> <mrow> <mrow> <mtext>th</mtext> <mtext> </mtext> </mrow> </mrow> </msup> </math> <math><msup><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msup></math> ionisation energy is high so atom contains 3 valence electrons. Hence, valency of the atom is 3 and the metal is trivalent. 4 mole of trivalent metal hydroxide will react with 6 mole of <math> <msub> <mrow> <mrow> <mi mathvariant="normal">H</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> <msub> <mrow> <mrow> <mi mathvariant="normal">S</mi> <mi mathvariant="normal">O</mi> </mrow> </mrow> <mrow> <mrow> <mn>4</mn> </mrow> </mrow> </msub> </math> <math><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub></math>, <math> <mfenced separators="|"> <mrow> <mrow> <mn>2</mn> <mi mathvariant="normal">M</mi> <mo> (</mo> <mi mathvariant="normal">O</mi> <mi mathvariant="normal">H</mi> <msub> <mrow> <mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> </msub> <mo>+</mo> <mn>3</mn> <msub> <mrow> <mrow> <mi mathvariant="normal">H</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> <msub> <mrow> <mrow> <mi mathvariant="normal">S</mi> <mi mathvariant="normal">O</mi> </mrow> </mrow> <mrow> <mrow> <mn>4</mn> </mrow> </mrow> </msub> <mo>? </mo> <msub> <mrow> <mrow> <mi mathvariant="normal">M</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> <msub> <mrow> <mrow> <mfenced separators="|"> <mrow> <mrow> <msub> <mrow> <mrow> <mi mathvariant="normal">S</mi> <mi mathvariant="normal">O</mi> </mrow> </mrow> <mrow> <mrow> <mn>4</mn> </mrow> </mrow> </msub> </mrow> </mrow> </mfenced> </mrow> </mrow> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> </msub> <mo>+</mo> <mn>6</mn> <msub> <mrow> <mrow> <mi mathvariant="normal">H</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> <mi mathvariant="normal">O</mi> </mrow> </mrow> </mfenced> </math>

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The five successive ionization enthalpies of an element are 710, 1414, 2550, 28124 and 33845 kJ mol?¹. How many moles of H?SO? will be needed to react completely with 4 moles of the metal hydroxide?

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