The following solutions were prepared by dissolving 10 g of glucose (C₆H₁₂O₆) in 250ml of water (P₁), 10 g of urea (CH₄N₂O) in 250ml of water (P₂) and 10 g of sucrose (C₁₂H₂₂O₁₁) in 250ml of water (P₃). The right option for the decreasing order of osmotic pressure of these solutions is :

Option 1 - <p>P₂ &gt; P₁ &gt; P₃</p>
Option 2 - <p>P₁ &gt; P₂ &gt; P₃<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>P₂ &gt; P₃ &gt; P₁<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>P₃ &gt; P₁ &gt; P₂</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 1
Detailed Solution:

π = iCRT
P? = 1 * (10/180) * R * T (For Glucose)
P? = 1 * (10/60) * R * T (For Urea)
P? = 1 * (10/342) * R * T (For Sucrose)

∴ P? > P? > P?

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

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