The gas phase reaction 2A(g) ? A?(g) At 400 K has ΔG° = +25.2 kJ mol?¹.
The equilibrium constant K? for this reaction is ________ *10?². (Round off to the nearest integer).
[ Use: R = 8.3 J mol?¹ K?¹, In10 = 2.3, log?? 2 = 0.30, 1atm = 1 bar]
[antilog (-0.3) = 0.501]

16 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago

ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp

o   3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering