The internal energy change (in J) when 90 g of water undergoes complete evaporation at 100°C is 
(Given: ΔH_vap for water at 373K = 41 kJ/mol, R = 8.314 JK?¹mol?¹)

4 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
R
7 months ago

189000 to 190000
Sol. ΔH = ΔU + Δn? RT
41000 * 5 = ΔU + 5 * 8.314 * 373
205000 = ΔU + 15505.61
ΔU = 189494.39 J = 189494 J

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry NCERT Exemplar Solutions Class 11th Chapter Two 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Two 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering