The internal energy change (in J) when 90 g of water undergoes complete evaporation at 100°C is
(Given: ΔH_vap for water at 373K = 41 kJ/mol, R = 8.314 JK?¹mol?¹)
The internal energy change (in J) when 90 g of water undergoes complete evaporation at 100°C is
(Given: ΔH_vap for water at 373K = 41 kJ/mol, R = 8.314 JK?¹mol?¹)
4 Views|Posted 7 months ago
Asked by Shiksha User
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R
Answered by
7 months ago
189000 to 190000
Sol. ΔH = ΔU + Δn? RT
41000 * 5 = ΔU + 5 * 8.314 * 373
205000 = ΔU + 15505.61
ΔU = 189494.39 J = 189494 J
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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