The ionic radii of F⁻ and O²⁻ respectively are 1.33 Å and 1.4 Å, while the covalent radius of N is 0.74 Å.
The correct statement for the ionic radius of N³⁻ from the following is:
The ionic radii of F⁻ and O²⁻ respectively are 1.33 Å and 1.4 Å, while the covalent radius of N is 0.74 Å.
The correct statement for the ionic radius of N³⁻ from the following is:
Option 1 - <p>It is smaller than O²⁻ and F⁻, but bigger than of N</p>
Option 2 - <p>It is bigger than F⁻ and N, but smaller than of O²⁻<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>It is smaller than F⁻ and N</p>
Option 4 - <p>It is bigger than O²⁻ and F⁻</p>
5 Views|Posted 7 months ago
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7 months ago
Correct Option - 1
Detailed Solution:
Anions have larger radii than atoms. Also, higher the e/p ratio higher the ionic radii. So, N? ³ > O? ² > F?
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
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the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Classification of Elements and Periodicity in Properties 2025
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