The longest wavelength doublet absorption transition is observed at 589 nm and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states

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Alok Kumar Singh | Contributor-Level 10

9 months ago

λ₁ = 589 nm = 589 x 10^-9 m

ν₁= c / λ₁= (3 x 10⁸ ms^-1) / (589 x 10^-9 m) = 5.0934 x 10¹⁴ s^-1

λ₂ = 589.6 nm = 589.6 x 10^-9 m

ν₂= c / λ₂= (3 x 10⁸ ms^-1) / (589.6 x 10^-9 m) = 5.0882 x 10¹⁴ s^-1

ΔE = E₁ – E₂ = h [ν₁– ν₂]

= (6.626 x 10^-34Js) x [ (5.0934 x 10¹⁴ s^-1) – (5.0882 x 10¹⁴ s^-1)

= 3.31 x 10^-22 J

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