The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between log(x/m) and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of x/m at a pressure of 4 atm is: [numerical value].
(Given log3 = 0.4771)
The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between log(x/m) and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of x/m at a pressure of 4 atm is: [numerical value].
(Given log3 = 0.4771)
Sol. (x/m) = k (P)¹/?
log (x/m) = logk + 1/n logP
Slope = 1/n = 2 So n = 1/2
Intercept ⇒ logk = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3² = 48
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