The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:    

[Given: The threshold frequency of platinum is 1.3 * 1015s-1 and h = 6.6 * 10-34 J s.]

Option 1 - <p>3.21 × 10<sup>-14</sup> J&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 2 - <p>6.24 × 10<sup>-16</sup> J&nbsp; &nbsp; &nbsp;&nbsp;</p>
Option 3 - <p>8.58 × 10<sup>-19</sup></p>
Option 4 - <p>9.76 × 10<sup>-20</sup> J</p>
2 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
V
8 months ago
Correct Option - 3
Detailed Solution:

? 0 = h υ 0

= 6 . 6 * 1 0 3 4 * 1 . 3 * 1 0 1 5 J

= 8 . 5 8 * 1 0 1 9 J

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