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The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:    

[Given: The threshold frequency of platinum is 1.3 × 1015s-1 and h = 6.6 × 10-34 J s.]

Option 1 -

3.21 * 10-14 J     

Option 2 -

6.24 * 10-16 J      

Option 3 -

8.58 * 10-19

Option 4 -

9.76 * 10-20 J

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    ? 0 = h υ 0

    = 6 . 6 × 1 0 − 3 4 × 1 . 3 × 1 0 1 5 J

    = 8 . 5 8 × 1 0 − 1 9 J

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