The minimum uncertainty in the speed of an electron in an one dimensional region of length 2a0 (Where a0 = Bohr radius 52.9 pm) is__________ km s-1. (Given: Mass of electron = 9.1 * 10-31 kg, Planck's constant h = 6.63 * 10-34 Js)

According to Heisenberg's uncertainly principle Δx*Δp=h4π ∴Δv=6.63*10−344*3.14*2*52.9*10−12*9.1*10−31 = 548273 ms-1

The minimum uncertainty in the speed of an electron in an one dimensional region of length 2a₀ (Where a₀ = Bohr radius 52.9 pm) is__________ km s^-¹.

**(Given: Mass of electron = 9.1 * 10^-³¹ kg, Planck's constant h = 6.63 * 10^-³⁴ Js)**

58 Views|Posted 8 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Vishal Baghel | Contributor-Level 10

8 months ago

According to Heisenberg's uncertainly principle

$Δ x * Δ p = \frac{h}{4 π}$

$∴ Δ v = \frac{6.63 * 1 0^{- 34}}{4 * 3.14 * 2 * 52.9 * 1 0^{- 12} * 9.1 * 1 0^{- 31}}$

= 548273 ms^-1

Upvote

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Chemistry NCERT Exemplar Solutions Class 12th Chapter Five 2025

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering