The molar conductivity of 0.007M acetic acid is 20 S² mol⁻¹. What is the dissociation constant of acetic acid? Choose the correct option.
[Λ°(H⁺) = 350 Scm² mol⁻¹]
[Λ°(CH₃COO⁻) = 50 Scm² mol⁻¹]
The molar conductivity of 0.007M acetic acid is 20 S² mol⁻¹. What is the dissociation constant of acetic acid? Choose the correct option.
[Λ°(H⁺) = 350 Scm² mol⁻¹]
[Λ°(CH₃COO⁻) = 50 Scm² mol⁻¹]
Option 1 -
1.75 * 10⁻⁴ mol⁻¹
Option 2 -
2.50 * 10⁻⁴ molL⁻¹
Option 3 -
1.75 * 10⁻⁵ molL⁻¹
Option 4 -
2.50 * 10⁻⁵ mol L⁻¹
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1 Answer
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Correct Option - 3
Detailed Solution:Λ°? (CH? COOH) = Λ°? (H? ) + Λ°? (CH? COO? ) = 350 + 50 = 400Scm² mol? ¹
α = Λ? / Λ°?
α = 20/400 = 5 × 10? ²
K? (CH? COOH) = Cα²
= 0.007 × (5 × 10? ²)²
= 1.75 × 10? molL? ¹
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