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The molar solubility of Zn(OH)2 in 0.1 M NaOH solution is x × 10-18M. The value of x is______.

(Nearest integer)

(Given: The solubility product of Zn(OH)2 is 2 × 10-20)

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago

    Z n ( O H ) 2 ? Z n 2 + + 2 O H −  

    S                           -            -

    NaOHNa+ + OH--

    0.1 M    -            -

    [ Z n 2 + ] = S                

    Here ; 2 × 10-20 = S (0.1)2

    So; S = 2 × 10-18 M

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