The molarity of the solution prepared by dissolving 6.3g of oxalic acid ( H 2 C 2 O 4 2 H 2 O )  in 250mL of water in mol L-1 is x * 10-2. The value of x is_________. (Nearest integer)

 [Atomic mass: H : 1.0, C : 12.0, O : 16.0]

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R
6 months ago

Molarity (M) = w * 1 0 0 0 m o l e c u l a r m a s s * v o l u m e o f s o l u t i o n ( m l )

= 6 . 3 * 1 0 0 0 1 2 6 * 2 5 0 = 4 2 0 = 0 . 2 M

Molecular mass of oxalic acid ( H 2 C 2 O 4 . 2 H 2 O )

= 1 * 2 + 12 * 2 + 16 * 4 + 2 * 18

              = 26 + 64 + 36 = 126

              M = 2 * 10-1 M

              = 20 * 10-2M

x * 1 0 2 = 2 0 * 1 0 2

x = 2 0

Ans. = 20

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