The oxide that given H2O2 most readily on treatment with H2O is:

(1) N a 2 O 2 + 2 H 2 O → 2 N a O H + H 2 O 2 <!- [if gte mso 9]><xml> </xml><! [endif]-> (2) B a O 2 . 8 H 2 O g i v e s H 2 O 2 <!- [if gte mso 9]><xml> </xml><! [endif]->after evaporation (3) PbO2 + 2H2O ->Pb (OH)4 (4) SnO2 + 2H2O ->Sn (OH)4

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P Block Elements Ncert Solutions Chemistry Class 12th Chemistry Class 12th

The oxide that given H₂O₂ most readily on treatment with H₂O is:

Option 1 -

Na₂O₂

Option 2 -

BaO₂ $\cdot$ 8H₂O

Option 3 -

PbO₂

Option 4 -

SnO₂

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

(1) $N a^{2} O_{2} + 2 H_{2} O \to 2 N a O H + H_{2} O_{2}$

(2) $B a O_{2} . 8 H_{2} O g i v e s H_{2} O_{2}$ after evaporation

(3) PbO₂ + 2H₂O ->Pb (OH)₄

(4) SnO₂ + 2H₂O ->Sn (OH)₄

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