The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x × 10-4. The value of x is ________. (Nearest integer)
[log 2.5 = 0.3979]
The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x × 10-4. The value of x is ________. (Nearest integer)
[log 2.5 = 0.3979]
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1 Answer
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50 ml of 1 (M) HCl + 30 ml of 1 (M) NaOH
NaOH + HCl -> NaCl + H2O
30 × 1 mmol 50 × 1 mmol
0 mmol 20 mmol
x = 6021
Ans. = 6021
Similar Questions for you
0.01 M NaOH,
M = 1 * 10-2
pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 0
Eqb. moles n(1 – a) na
total moles =
Eqb. pressure
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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