The photoelectric current from Na (work function, w? = 2.3eV) is stopped by the output voltage of the cell
Pt(s)/H?(g, 1 bar) | HCl (aq., pH = 1)|AgCl(s)|Ag(s).
The pH of aq. HCl required to stop the photoelectric current from K(w? = 2.25 eV), all other conditions remaining the same, is * 10?² (to the nearest integer).
Given,
2.303(RT/F) = 0.06 V; E°(AgCl|Ag|Cl?) = 0.22 V
The photoelectric current from Na (work function, w? = 2.3eV) is stopped by the output voltage of the cell
Pt(s)/H?(g, 1 bar) | HCl (aq., pH = 1)|AgCl(s)|Ag(s).
The pH of aq. HCl required to stop the photoelectric current from K(w? = 2.25 eV), all other conditions remaining the same, is * 10?² (to the nearest integer).
Given,
2.303(RT/F) = 0.06 V; E°(AgCl|Ag|Cl?) = 0.22 V
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Four 2025
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