The position of −Br in the compound in CH₃CH=CHC(Br)(CH₃)₂ can be classified as

(i) Allyl

(ii) Aryl

(iii) Vinyl

(iv) Secondary

<p><span data-teams="true">This is a multiple choice answer as classified in NCERT Exemplar</span></p><p>The correct answer is Option (i).</p><p>When the halogen atom is linked to an sp³-hybridised carbon atom next to an allylic carbon, a carbon-carbon double bond is formed.</p><p>Aryl halides are produced when a halogen atom is directly linked to an aromatic ring's sp²-hybridised carbon atom.</p><p>When a halogen atom is linked to a sp²-hybridised carbon atom in a carbon-carbon double bond, vinylic bonds are produced. Simply defined, it's an ethylene molecule with one hydrogen atom substituted by another -R group.</p><p>When the halogen is attached to a secondary carbon atom in the molecule, secondary bonds form. The −Br is linked to a tertiary carbon atom in the supplied molecule, which is then bonded to an sp³-hybridised carbon-carbon double bond. As a result, this −Br has an allylic position.&nbsp;</p>

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