Chemistry Chemical Kinetics Class 12th Chemistry

The rate constant of a reaction increases by five times on increase in temperature from 27°C to 52°C. The value of activation energy in kJ mol^-1 is……….. (Rounded-off to the nearest integer).

[R = 8.314JK^-1mol^-1]

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Payal Gupta | Contributor-Level 10

7 months ago

$l o g (\frac{k_{2}}{k_{1}}) = \frac{E a}{2.303 * 8.314} [\frac{1}{300} - \frac{1}{325}]$

log (5) = $\frac{E a}{2.303 * 8.314} [\frac{1}{300} - \frac{1}{325}]$

$∴ E a = \frac{0.7 * 2.303 * 8.314 * 300 * 325}{25} = 52271.7$

Ea in kJ/mole = $\frac{52271.7}{1000} = 52.2 k J / m o l$

the nearest integer is 52.

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