This is a multiple choice answer as classified in NCERT Exemplar
The Correct Answer is Option (iv).
By electrophilic substitution, aromatic arenes react with chlorine in the presence of Lewis acid catalysts such as iron (III) chloride, yielding ortho and para isomers of haloarenes. (ii) and (iii) are both products of the reaction. Cl2 forms a coordination complex with FeCl3, creating the Cl + FeCl4 - complex, which has a small positive charge on Cl and a negative charge on FeCl4 - . This Cl+ then interacts with the aromatic double bonds of the toluene molecule to create an addition product, which is su
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This is a multiple choice answer as classified in NCERT Exemplar
The Correct Answer is Option (iv).
By electrophilic substitution, aromatic arenes react with chlorine in the presence of Lewis acid catalysts such as iron (III) chloride, yielding ortho and para isomers of haloarenes. (ii) and (iii) are both products of the reaction. Cl2 forms a coordination complex with FeCl3, creating the Cl + FeCl4 - complex, which has a small positive charge on Cl and a negative charge on FeCl4 - . This Cl+ then interacts with the aromatic double bonds of the toluene molecule to create an addition product, which is subsequently deprotonated to form a mixture of o-, p-, and m- chlorotoluene isomers. Because the m- isomer is highly unstable, the product is not accessible in the o- and p- forms.
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<p><span data-teams="true">This is a multiple choice answer as classified in NCERT Exemplar</span></p><p>The Correct Answer is Option (iv).</p><p>By electrophilic substitution, aromatic arenes react with chlorine in the presence of Lewis acid catalysts such as iron (III) chloride, yielding ortho and para isomers of haloarenes. (ii) and (iii) are both products of the reaction. <strong>Cl<sub>2</sub></strong> forms a coordination complex with <strong>FeCl<sub>3</sub></strong>, creating the <strong>Cl + FeCl<sub>4</sub> - </strong>complex, which has a small positive charge on <strong>Cl</strong> and a negative charge on <strong>FeCl<sub>4</sub> - </strong>. This <strong>Cl<sup>+</sup> </strong> then interacts with the aromatic double bonds of the toluene molecule to create an addition product, which is subsequently deprotonated to form a mixture of o-, p-, and m- chlorotoluene isomers. Because the m- isomer is highly unstable, the product is not accessible in the o- and p- forms.</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1746522755phpIXCzDS_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1746522755phpIXCzDS.jpeg" alt="" width="290" height="135"></picture></div></div>
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