The shortest wavelength of H atom in the Lyman series is λ₁. The longest wavelength in the Balmer Series of H⁺ is:
The shortest wavelength of H atom in the Lyman series is λ₁. The longest wavelength in the Balmer Series of H⁺ is:
Option 1 -
5λ₁/9
Option 2 -
36λ₁/5
Option 3 -
9λ₁/5
Option 4 -
27λ₁/5
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:For hydrogen atom :
For Lyman series n? = 1 & n? = ∞
1/λH = RH [1/1² - 1/∞²] So, λ = 1/RH
For He? ion Balmer series n? = 2 & n? = 3
1/λHe? = RH × Z² [1/n? ² - 1/n? ²]
1/λHe? = RH × 4 × [1/4 - 1/9] = RH × 4 × (5/36)
1/λHe? = (5/9)RH = (5/9) (1/λ)
(λHe? ) = (9/5)λ
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