The solubility product of Al(OH)3 is 2.7 × 10–11. Calculate its solubility in gL–1 and also find out pH of this solution. (Atomic mass of Al = 27 u).
The solubility product of Al(OH)3 is 2.7 × 10–11. Calculate its solubility in gL–1 and also find out pH of this solution. (Atomic mass of Al = 27 u).
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1 Answer
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This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: Let us assume S be the solubility of Al (OH)3.
Ksp= [Al3+] [OH-]3= (S) (3S)3=27S4
S4=27Ksp=27 × 1027 × 10-11=1 × 10-12
S=1×10−3 mol L-1.
(i) Solubility of Al (OH)3 ? : Molar mass of Al (OH)3 is 78g. Hence, solubility of Al (OH)3 ? in gL-1=1 × 103 × 78gL-1=78 × 10-3gL1=7.8 × 10-2gL-1
(ii) pH of the solution: S=1× 10−3mol L-1OH=3S= 3×1× 10−3 = 3× 10&m
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