The species that has a spin-only magnetic moment of 5.9BM, is: (Td=tetrahedral)
The species that has a spin-only magnetic moment of 5.9BM, is: (Td=tetrahedral)
Option 1 - <p>[Ni(CN)₄]²⁻ (square planar)</p>
Option 2 - <p>[NiCl₄]²⁻ (Td)</p>
Option 3 - <p>Ni(CO)₄ (Td)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>[MnBr₄]²⁻ (Td)</p>
6 Views|Posted 7 months ago
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7 months ago
Correct Option - 4
Detailed Solution:
µ=5.9 B.M ⇒ 5 unpaired electrons. [MnBr? ]²?
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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