The spin only magnetic moment value of an octhahedral complex among CoCl₃.4NH₃, NiCl₂.6H₂O and PtCl₄.2HCl, which upon reaction with excess of AgNO₃ gives 2 moles of AgCl is____________B. M. (Nearest integer)

For precipitation of two moles of AgCl

Two Cl will produce as a free anion

CoCl₃.4NH₃ complex will $\left[CO{\left(N{H}_3\right)}_{4}C{l}_2\right]$ Cl (will not give 2Cl)

$PtC{l}_4.2HCl\to$ complex will be H2 [PtCl6] will not any Cl

$NiC{l}_2.6H_{2}O\to \left[Ni{\left(H_{2}O\right)}_6\right]C{l}_2$ will produce two Cl ion.

${\left[Ni{\left(H_{2}O\right)}_6\right]}^{++}+2C{l}^{-}\underset{AgN{O}_3}{\overset{}{\to }}2AgCl\left(s\right)$ precipitate formation

$N{i}^{2+}\to \left[Ar\right]3d^{8}4s^0$

$\mu =\sqrt[]{2\left(2+2\right)}=\sqrt[]{8}=2.84BM=3$

<p>For precipitation of two moles of AgCl</p><p>Two Cl will produce as a free anion</p><p>CoCl₃.4NH₃ complex will&nbsp;<math><mrow><mrow><mo> [</mo><mrow><mi>C</mi><mi>O</mi><msub><mrow><mrow><mo> (</mo><mrow><mi>N</mi><msub><mrow><mi>H</mi></mrow><mrow><mn>3</mn></mrow></msub></mrow><mo>)</mo></mrow></mrow><mrow><mn>4</mn></mrow></msub><mi>C</mi><msub><mrow><mi>l</mi></mrow><mrow><mn>2</mn></mrow></msub></mrow><mo>]</mo></mrow></mrow></math>&nbsp;Cl (will not give 2Cl)</p><p><math><mrow><mi>P</mi><mi>t</mi><mi>C</mi><msub><mrow><mi>l</mi></mrow><mrow><mn>4</mn></mrow></msub><mo>.</mo><mn>2</mn><mi>H</mi><mi>C</mi><mi>l</mi><mo>→</mo></mrow></math>&nbsp;complex will be H2 [PtCl6] will not any Cl</p><p><math><mrow><mi>N</mi><mi>i</mi><mi>C</mi><msub><mrow><mi>l</mi></mrow><mrow><mn>2</mn></mrow></msub><mo>.</mo><mn>6</mn><msub><mrow><mi>H</mi></mrow><mrow><mn>2</mn></mrow></msub><mi>O</mi><mo>→</mo><mrow><mo> [</mo><mrow><mi>N</mi><mi>i</mi><msub><mrow><mrow><mo> (</mo><mrow><msub><mrow><mi>H</mi></mrow><mrow><mn>2</mn></mrow></msub><mi>O</mi></mrow><mo>)</mo></mrow></mrow><mrow><mn>6</mn></mrow></msub></mrow><mo>]</mo></mrow><mi>C</mi><msub><mrow><mi>l</mi></mrow><mrow><mn>2</mn></mrow></msub></mrow></math>&nbsp;will produce two Cl ion.</p><p><math><mrow><msup><mrow><mrow><mo> [</mo><mrow><mi>N</mi><mi>i</mi><msub><mrow><mrow><mo> (</mo><mrow><msub><mrow><mi>H</mi></mrow><mrow><mn>2</mn></mrow></msub><mi>O</mi></mrow><mo>)</mo></mrow></mrow><mrow><mn>6</mn></mrow></msub></mrow><mo>]</mo></mrow></mrow><mrow><mo>+</mo><mo>+</mo></mrow></msup><mo>+</mo><mn>2</mn><mi>C</mi><msup><mrow><mi>l</mi></mrow><mrow><mo>−</mo></mrow></msup><munderover><mo>→</mo><mrow><mi>A</mi><mi>g</mi><mi>N</mi><msub><mrow><mi>O</mi></mrow><mrow><mn>3</mn></mrow></msub></mrow><mrow></mrow></munderover><mn>2</mn><mi>A</mi><mi>g</mi><mi>C</mi><mi>l</mi><mrow><mo> (</mo><mrow><mi>s</mi></mrow><mo>)</mo></mrow></mrow></math>&nbsp;precipitate formation</p><p><math><mrow><mi>N</mi><msup><mrow><mi>i</mi></mrow><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>→</mo><mrow><mo> [</mo><mrow><mi>A</mi><mi>r</mi></mrow><mo>]</mo></mrow><mn>3</mn><msup><mrow><mi>d</mi></mrow><mrow><mn>8</mn></mrow></msup><mn>4</mn><msup><mrow><mi>s</mi></mrow><mrow><mn>0</mn></mrow></msup></mrow></math></p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752836292phpOYFtxl.jpeg" alt="" width="300" height="82" loading="lazy"></picture></div></div><p><math><mrow><mi>μ</mi><mo>=</mo><mroot><mrow><mn>2</mn><mrow><mo> (</mo><mrow><mn>2</mn><mo>+</mo><mn>2</mn></mrow><mo>)</mo></mrow></mrow><mrow></mrow></mroot><mo>=</mo><mroot><mrow><mn>8</mn></mrow><mrow></mrow></mroot><mo>=</mo><mn>2</mn><mo>.</mo><mn>8</mn><mn>4</mn><mi>B</mi><mi>M</mi><mo>=</mo><mn>3</mn></mrow></math></p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment