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The strengths of 5.6 volume hydrogen peroxide (of density $1 g / m L$ ) in terms of mass percentage and molarity $(M)$ , respectively, are:

(Take molar mass of hydrogen peroxide as $34 g / m o l$ )

Option 1 -

0.85 and 0.25

Option 2 -

0.85 and 0.5

Option 3 -

1.7 and 0.5

Option 4 -

1.7 and 0.25

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

For $H_{2} O_{2}$

Molarity $= \frac{Volume strength}{11.2} = \frac{5.6}{11.2} = 0.5 M$

Molarity $= \frac{% (w / w) \times 10 \times d}{G M M}$

$0.5 = \frac{% (w / w) \times 10 \times d}{34}$

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The strengths of 5.6 volume hydrogen peroxide (of density $1 g / m L$ ) in terms of mass percentage and molarity $(M)$ , respectively, are:

(Take molar mass of hydrogen peroxide as $34 g / m o l$ )

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The strengths of 5.6 volume hydrogen peroxide (of density 1 g / m L ) in terms of mass percentage and molarity ( M ) , respectively, are: (Take molar mass of hydrogen peroxide as 34 g / m o l )

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The strengths of 5.6 volume hydrogen peroxide (of density $1 g / m L$ ) in terms of mass percentage and molarity $(M)$ , respectively, are:

(Take molar mass of hydrogen peroxide as $34 g / m o l$ )