The value of ∆fHᶱ for NH3 is – 91.8 kJ/ mol. Calculate enthalpy change for the following reaction :
2NH3(g) → N2(g) + 3H2(g)
The value of ∆fHᶱ for NH3 is – 91.8 kJ/ mol. Calculate enthalpy change for the following reaction :
2NH3(g) → N2(g) + 3H2(g)
This is a Short Answer Type Questions as classified in NCERT Exemplar
ΔH for formation is given. For the reverse reaction, ΔHchanges sign as the reverse of exothermic reaction will be endothermic. So, ΔH for decomposition is - (-91.8)=91.8 for one mole. But here, two moles are decomposing,
ΔH=2*91.8=
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