The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 x 105 m s-1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

ν = 4.37 x 105 m s-1, m = 0.1 kgAs per de Brogile’s equation, λ= m/v = (6.626 x 10-34 kg m2 s-1) / (0.1 kg) x (4.37 x 105 m s-1)=6.626/0.437 x 10-34-5 m= 1.516 x 10-38 m

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Ncert Solutions Chemistry Class 11th Chemistry Class 11th Structure of Atoms

The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 x 10⁵ m s^-1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

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alok kumar singh | Contributor-Level 10

3 months ago

ν = 4.37 x 10⁵ m s^-1, m = 0.1 kg

As per de Brogile’s equation,

λ= m/v = (6.626 x 10^-34 kg m²s^-1) / (0.1 kg) x (4.37 x 10⁵ m s^-1)

=6.626/0.437 x 10^-34-5 m

= 1.516 x 10^-38 m

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