The volume, in mL, of 0.02M K₂Cr₂O₇ solution required to react with 0.288 g of ferrous oxalate in acidic medium is (Molar mass of Fe = 56 mol⁻¹)
The volume, in mL, of 0.02M K₂Cr₂O₇ solution required to react with 0.288 g of ferrous oxalate in acidic medium is (Molar mass of Fe = 56 mol⁻¹)
50.00
K? Cr? O? + FeC? O? → Fe³? + CO? + Cr³? + K? + H? O
n_f=6 n_f=3
Now apply equivalent concept
0.02 * 6 * V = (0.288 / (144/3) * 10³
Normality
V = (0.288 * 10³)/ (48 * 6 * 0.02) = 50.00 mL
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