Thermodynamic feasibility of the reaction alone cannot decide the rate of the reaction. Explain with the help of one example

<p>This is a Short Answer Type Question as classified in NCERT Exemplar</p><p>Thermodynamic feasibility is determined by&nbsp;<strong>Δ</strong><strong>G</strong> factors. So, while the conversion of diamond to graphite is thermodynamically viable, the reaction is sluggish and has a high activation energy.</p><p>&nbsp;</p><p>Gibb's free energy is <strong>Δ</strong><strong>G</strong><br><strong>Δ</strong><strong>G =Rtlnk</strong></p><p><strong>Δ</strong><strong>G_{P, T <span contenteditable="false"> <math> <mo>&gt;</mo> </math> </span>}</strong><strong>_&nbsp;</strong>o</p><p>at constant pressure and temperature should be negative or less than 0.</p><p>For example, Diamond to be converted to Graphite</p><p><strong>Δ</strong><strong>G</strong><strong>=−</strong><strong>ve</strong></p><p>&nbsp;</p><p>It is theoretically conceivable, but the rate is extremely slow, and the activation energy is extremely high. The energy required to transform diamond to graphite is insufficient.</p>

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