Through a ZnSO₄ solution, 0.015 A current was passed for 15 minutes. What is the mass of Zn deposited? (in mg)

(Atomic weight of Zn = 65.4 )

2 Views|Posted 4 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Alok Kumar Singh | Contributor-Level 10

4 months ago

Charge passed = It

= 0.015 * 15 * 60 C

Moles of electrons passed $= \frac{0.015 * 15 * 60}{96500}$

Moles of Zn deposited = $\frac{1}{2} * \frac{0.015 * 15 * 60}{96500}$

= 0.00007

Mass of Zn deposited = 0.00007 * 65.4 g = 4.58mg

Upvote

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Chemistry Electrochemistry 2025

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering

Through a ZnSO4 solution, 0.015 A current was passed for 15 minutes. What is the mass of Zn deposited? (in mg) (Atomic weight of Zn = 65.4 )

Similar Questions for you