Two statement are given below:

Statement I : The melting point of monocarboxylic acid even number of carbon atoms is higher than that of with odd number of carbon atoms acid immediately below and above it in the series.

Statement II :  The solubility of monocarboxylic acids in water decreases with increases in molar mass.

Choose the most appropriate options

Option 1 - <p>Both <strong>Statement I </strong>and <strong>Statement II </strong>are correct.</p>
Option 2 - <p>Both <strong>Statement I </strong>and <strong>Statement II </strong>are incorrect.</p>
Option 3 - <p><strong>Statement I </strong>is correct but <strong>Statement II </strong>is incorrect.</p>
Option 4 - <p><strong>Statement I </strong>is incorrect but <strong>Statement II</strong> is correct.</p>
4 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
6 months ago
Correct Option - 1
Detailed Solution:

Melting point of monocarboxylic acids with even number of carbon is more than that with odd number of carbon due to lattice energy.

With increase in molar mass of monocarboxylic acids size of alkyl group (Hydrophobic portion) increases and therefore solubility in water decreases.

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.8L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Ncert Solutions Class 12th 2023

Chemistry Ncert Solutions Class 12th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering