Using valence bond theory, explain the following in relation to the complexes given below:
[Mn(CN)6]3- ,[Co(NH3)6]3+ ,[Cr(H2O)6]3+ ,[FeCl]4-
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value
Using valence bond theory, explain the following in relation to the complexes given below:
[Mn(CN)6]3- ,[Co(NH3)6]3+ ,[Cr(H2O)6]3+ ,[FeCl]4-
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value
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1 Answer
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This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans:
[Mn (CN)6]3−
Electronic configuration is Mn3+= [Ar]3 d4 hence box electronic structure
(i) Type of hybridisation d2sp3
(ii) Inner orbital complex
(iii) paramagnetic, due to presence of three unpaired electrons.
(iv) Spin only magnetic moment is calculated using the formula : n=2 in this case, we get spin only magnetic moment in BMas = = = 2.87BM
[Co (NH3)6]3+
Electronic configuration of Co3+= [Ar]3 d6
(i) Hyb As shown in the above box electronic structure the type of hybridisation is . d2sp3
(ii) Inner orbital complex
(iii) Diama
...more
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