Value of Kp for the equilibrium reaction N2O4(g) ?  2NO2(g) at 288 K is 47.9. The Kc for this reaction at same temperature is_________. (Nearest integer)

(R = 0.083 L bar K-1 mol-1)

3 Views|Posted 7 months ago
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7 months ago

Kp = 47.9      T = 288 K

KC =?                    R = 0.083 L bar/K mol

N 2 O 4 ( g ) ? 2 N O 2 ( g )           

Using

K p = K C ( R T ) Δ n g              

Here ;

Δ n g = 1                

49.7 = KC (0.083 * 288)1

KC = 2

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