We know that the relationship between Kc and Kp is
Kp = Kc (RT)∆n What would be the value of ∆n for the reaction
NH4Cl (s) ⇌ NH3 (g) + HCl (g)
(i) 1
(ii) 5
(iii) 5
(iv) 2
We know that the relationship between Kc and Kp is
Kp = Kc (RT)∆n What would be the value of ∆n for the reaction
NH4Cl (s) ⇌ NH3 (g) + HCl (g)
(i) 1
(ii) 5
(iii) 5
(iv) 2
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option(iv)
The relationship between Kp and Kc is
Kp=Kc(RT)Δn
Where ?n = (number of moles of gaseous products) – (number of moles of gaseous reactants)
For the reaction,
NH4C1(s)?NH3(g)+HCl(g)
Δn=2–0=2
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025
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