What is Kolbe’s Electrolysis for symmetrical alkenes?

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  • Kolbe's electrolysis is a process where an aqueous solution of sodium and potassium salt undergoes electrolysis to lead to the formation of a symmetrical alkene. Principle of this technique is that at anode, the carboxylate ion undergoes oxidation and loses carbon dioxide (CO? ). Similarly, at cathode the water decomposes to form hydrogen gas. The alkyl radicals formed in these two cases combine to form alkenes.

Similar Questions for you

V
Vishal Baghel

Stability order :
Conjugate > Isolated > Cumulative and (y) is Anti aromatic.
HOC ∝ 1 / (Stability of Alkene)

R
Raj Pandey

Kindly consider the following Image

 

A
Aadit Singh Uppal

According to this rule, when a hydrogen halide (HX) or water is added to an asymmetrical alkene, the hydrogen atom (H) gets attached to the carbon atom of the double bond which has more hydrogen atoms, and the halide (X) or OH group attaches to the carbon atom which has fewer hydrogen atoms.

A
Aadit Singh Uppal

The most common method used for the identification of alkenes is the bromine water test. We simply have to add a few drops of bromine water to the compound which is to be identified. If the compound actually is an alkene, the reddish brown colour will get decolorized (? bond reacts with bromine and breaks the double bond).

R
Raj Pandey

C? H? → possible structure of C? H? are; CH? -C (CH? )=CH? and CH? -CH=CH-CH?
(Unsaturation factor = 1)
Ozonolysis of CH? -C (CH? )=CH? gives acetone (B) and formaldehyde.
Oxidation of CH? -C (CH? )=CH? with KMnO? /H? gives acetone (B) and CO?
The question states it gives C? H? O (B). Hence the alkene is 2-Methylpropene (A).
[Reaction scheme showing ozonolysis and permanganate oxidation of 2-methylpropene]

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