What will be the value of pH of 0.01 mol dm–3 CH3COOH (Ka = 1.74 * 10–5 )?
(i) 3.4
(ii) 3.6
(iii) 3.9
(iv) 3.0
What will be the value of pH of 0.01 mol dm–3 CH3COOH (Ka = 1.74 * 10–5 )?
(i) 3.4
(ii) 3.6
(iii) 3.9
(iv) 3.0
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: option (i)
pH for weak acid is given by the following equation:
pH= [pKa−logC]
= [−log (1.74*10−5)−log0.01]
=3.4
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pH = 2
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36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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