When 35 mL of 0.15 M lead nitrate solution is mixed with 20mL of 0.12 M chromic sulphate solution, __________ *10⁻⁵ moles of lead sulphate precipitate out.
When 35 mL of 0.15 M lead nitrate solution is mixed with 20mL of 0.12 M chromic sulphate solution, __________ *10⁻⁵ moles of lead sulphate precipitate out.
This is a limiting reactant problem. The initial moles are 5.25 mmol of Pb (NO? )? and 2.4 mmol of Cr? (SO? )? Based on the 3:1 stoichiometric ratio, Pb (NO? )? is the limiting reactant. The moles of PbSO? formed are equal to the initial moles of the limiting reactant, which is 5.25 mmol or 5.25 * 1
Similar Questions for you
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
Rate of ESR ∝ No. of α – H (Hyperconjugation)
Cr3+ion is a most stable in aqueous solution due to. t2g half filled configuration
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry Solutions 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering



