When 600 mL of 0.2 M HNO3 is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is_________ * 10-2 °C.

(Enthalpy of neutralization = 57 kJ mol-1 and Specific heat of water = 4.2 JK-1 g-1)

(Neglect heat capacity of flask)

13 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
P
8 months ago

 ΔH=165kJ/mole

T =?

ΔS=550JK1

At equilibrium ; ΔG=0

T=ΔHΔS=165*1000550K

=3*100K=300K

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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