When 800mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x × 10-2M. (Nearest Integer)
(Molar mas of nitric acid is 63g mol-1)
When 800mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x × 10-2M. (Nearest Integer)
(Molar mas of nitric acid is 63g mol-1)
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1 Answer
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Remaining volume of solution = 400 ml
Mass of HNO3 = 25.2 – 11.5 = 13.7
Molarity = = 0.54 M = 54 × 10-2 M
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