Which of the following options does not represent ground state electronic configuration of an atom? (i) 1s2 2s2 2p6 3s2 3p6 3d8 4s2 (ii) 1s2 2s2 2p6 3s2 3p6 3d9 4s2 (iii) 1s2 2s2 2p6 3s2 3p6 3d10 4s1 (iv) 1s2 2s2 2p6 3s2 3p6 3d5 4s1

Which of the following options does not represent ground state electronic configuration of an atom?

(i) 1s²2s² 2p⁶ 3s² 3p⁶3d⁸ 4s²

(ii) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁹4s²

(iii) 1s² 2s²2p⁶ 3s² 3p⁶3d¹⁰ 4s¹

(iv) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹

2 Views|Posted 9 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Vishal Baghel | Contributor-Level 10

9 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (ii) 1s²2s² 2p⁶ 3s²3p⁶3d⁹4s²

As per the Hund's rule the half-filled and fully filled orbital leads to the extra stability due to the symmetry thus fully filled 3d and half-filled 4s is preferred.

Upvote

Similar Questions for you

Find out the number of following orders which are INCORRECT against the mentioned properties:

(i) Ortho hydrogen > Para hydrogen (Stability at low temperature)

(ii) Ethanol > Glycerol (Viscosity)

(iii) D₂ < He (Boiling point)

(iv) HF > H₂O (Melting point)

(v) H₃BO₃ > BF₃ (Melting point)

(vi) NH₃ < SbH₃ (Boiling point)

(vii) H₂O₂ > H₂O (Strength of hydrogen bond)

(viii) H₂O < D₂O (Freezing point)

(ix) $H F_{2}^{Θ}$ < HF (Strength of hydrogen bond)

(x) D₂O < H₂O (Bond energy)

Vishal Baghel

Kindly go through the answers

(7.00)

Consider the following reaction:
(A substituted phenol reacts with H? and CrO?Cl to produce product 'P'.)
The product ‘P’ gives positive acetyl chloride test. This is because of the presence of which of these –OH group(s)?


Raj Pandey

Kindly consider the following Image

The number of radial land angular nodes in 4d orbital are, respectively

Payal Gupta

In 4d orbital, n = 4 and $l = 2$

Radial nodes = $n - l - 1$

Radial nodes = 4 – 2 – 1 = 1

And angular nodes, $l = 2$

The spin-only magnetic moment value of species is________× 10^-2 BM. (Nearest integer)

[Given:  $\sqrt[]{3} = 1.73]$

Alok Kumar Singh

$B_{2}^{+} \to σ 1 s^{2} s * 1 s^{2} σ 2 s^{2} σ * 2 s^{2} π 2 p^{1}$

Here, number of unpaired electrons, n = 1

Spin only moment ; $μ = \sqrt[]{n (n + 2)} B . M$

= 173 × 10^-2 B.M

Vishal Baghel

$Δ H = Δ U + Δ (P V)$

= $Δ U + P Δ V + V Δ P$

= $Δ U + P Δ V$ (At constant pressure)

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Chemistry NCERT Exemplar Solutions Class 11th Chapter Two 2025

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering