Ask & Answer Question

Some Basic Concepts of Chemistry Ncert Solutions Chemistry Class 11th Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter One

Which of the following pairs have the same number of atoms?

(A) 16g of O₂ and 4g of H2

(B) 16g of O₂ and 44g of CO₂

(c) 28g of N₂and 32g of O₂

(D) 12g of c and 23g of Na

3 Views | Posted 3 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

3 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option(C), (D)

(A) The number of moles is given by the following formula,

Moles = $\frac{M a s s}{M o l a r m a s s}$ -----------(1)

The number of moles of O₂ is calculated by using equation (1) as follows,

Moles of O₂= $\frac{16 g}{32 g / m o l}$ = 0.5 mol

The number of atoms can be calculated as, number of moles

$\frac{n u m b e r o f a t o m s}{A v o g a d r o s n u m b e r}$ -----------(2)

On substituting the values in the equation (2)

0.5 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 0.5 $*$ 6.022 $*$ 10²³

The number of moles of H₂ is calculated by using equation (1) as follows,

Moles of H₂= $\frac{4 g}{2 g / m o l}$

= 2 mol

On substituting the values in the equation (2):

2 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 2 $*$ 6.022 $*$ 10²³

(B) The number of moles o

...more

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option(C), (D)

(A) The number of moles is given by the following formula,

Moles = $\frac{M a s s}{M o l a r m a s s}$ -----------(1)

The number of moles of O₂ is calculated by using equation (1) as follows,

Moles of O₂= $\frac{16 g}{32 g / m o l}$ = 0.5 mol

The number of atoms can be calculated as, number of moles

$\frac{n u m b e r o f a t o m s}{A v o g a d r o s n u m b e r}$ -----------(2)

On substituting the values in the equation (2)

0.5 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 0.5 $*$ 6.022 $*$ 10²³

The number of moles of H₂ is calculated by using equation (1) as follows,

Moles of H₂= $\frac{4 g}{2 g / m o l}$

= 2 mol

On substituting the values in the equation (2):

2 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 2 $*$ 6.022 $*$ 10²³

(B) The number of moles of CO₂ is calculated by using equation (1) as follows

Moles of CO₂ = $\frac{44 g}{44 g / m o l}$

= 1 mol

On substituting the values in the equation (2), the number of atoms can be calculated as ,

1 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 1 $*$ 6.022 $*$ 10²³

(C) The number of moles of N₂ is calculated by using equation (1) as follows,

Moles of N₂= $\frac{28 g}{28 g / m o l}$ =1 mol

On substituting the values in the equation (2), the number of molecules can be calculated as

1 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 1 $*$ 6.022 $*$ 10²³

The number of moles of O₂ is calculated by using equation (1) as follows,

Moles of O₂= $\frac{32 g}{32 g / m o l}$ = 1

The number of atoms can be calculated as, number of moles

$\frac{n u m b e r o f a t o m s}{A v o g a d r o s n u m b e r}$ -

On substituting the values in the equation (2)

1 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 1 $*$ 6.022 $*$ 10²³

(D) The number of moles of C is calculated by using equation (1) as follows,

Moles of C = $\frac{12 g}{12 g / m o l}$ =1 mol

On substituting the values in the equation (2), the number of molecules can be calculated as

1 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 1 $*$ 6.022 $*$ 10²³

The number of moles of Na is calculated by using equation (1) as fo

Moles of Na = $\frac{23 g}{23 g / m o l}$ =1 mol

On substituting the values in the equation (2), the number of molecules can be calculated as

1 mol = $\frac{n u m b e r o f a t o m s}{6.022 * 10^{23}}$

number of atoms = 1 $*$ 6.022 $*$ 10²³

less

This is a Multiple Choice Questions as classified in NCERT ExemplarOption(C), (D)(A) The number of moles is given by the following formula,Moles = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal">s</mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> <mi mathvariant="normal"> </mi> </math> -----------(1)The number of moles of O2 is calculated by using equation (1) as follows,Moles of O2 = <math> <mfrac> <mrow> <mrow> <mn>16</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>32</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math>  = 0.5 molThe number of atoms can be calculated as, number of moles <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">A</mi> <mi mathvariant="normal">v</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">d</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> <mi mathvariant="normal"> </mi> </math> -----------(2)On substituting the values in the equation (2)0.5 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 0.5 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023The number of moles of H2 is calculated by using equation (1) as follows,Moles of H2 = <math> <mfrac> <mrow> <mrow> <mn>4</mn> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> = 2 molOn substituting the values in the equation (2):2 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 2 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023(B) The number of moles of CO2 is calculated by using equation (1) as followsMoles of CO2 = <math> <mfrac> <mrow> <mrow> <mn>44</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>44</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> = 1 molOn substituting the values in the equation (2), the number of atoms can be calculated as ,1 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 1 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023(C) The number of moles of N2 is calculated by using equation (1) as follows,Moles of N2 = <math> <mfrac> <mrow> <mrow> <mn>28</mn> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>28</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math>  =1 molOn substituting the values in the equation (2), the number of molecules can be calculated as1 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 1 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023The number of moles of O2 is calculated by using equation (1) as follows,Moles of O2 = <math> <mfrac> <mrow> <mrow> <mn>32</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>32</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math>  = 1The number of atoms can be calculated as, number of moles <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">A</mi> <mi mathvariant="normal">v</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">d</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> <mi mathvariant="normal"> </mi> </math> -On substituting the values in the equation (2)1 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 1 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023(D) The number of moles of C is calculated by using equation (1) as follows,Moles of C = <math> <mfrac> <mrow> <mrow> <mn>12</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>12</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> =1 molOn substituting the values in the equation (2), the number of molecules can be calculated as1 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 1 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023The number of moles of Na is calculated by using equation (1) as foMoles of Na = <math> <mfrac> <mrow> <mrow> <mn>23</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> <mo>/</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> =1 molOn substituting the values in the equation (2), the number of molecules can be calculated as1 mol = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> <mrow> <mrow> <mn>6.022</mn> <mo>×</mo> <mi mathvariant="normal"> </mi> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>23</mn> </mrow> </mrow> </msup> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> number of atoms = 1 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 6.022 <math> <mo>×</mo> <mi mathvariant="normal"> </mi> </math> 1023

0 Upvotes 0 Downvotes

Which of the following pairs have the same number of atoms?

(A) 16g of O₂ and 4g of H2

(B) 16g of O₂ and 44g of CO₂

(c) 28g of N₂and 32g of O₂

(D) 12g of c and 23g of Na

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

Which of the following pairs have the same number of atoms? (A) 16g of O2 and 4g of H2 (B) 16g of O2 and 44g of CO2 (c) 28g of N2 and 32g of O2 (D) 12g of c and 23g of Na

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

Which of the following pairs have the same number of atoms?

(A) 16g of O₂ and 4g of H2

(B) 16g of O₂ and 44g of CO₂

(c) 28g of N₂and 32g of O₂

(D) 12g of c and 23g of Na